52x^2-55x-63=0

Solution for 52x^2-55x-63=0 equation:

52x^2-55x-63=0

a = 52; b = -55; c = -63;
Δ = b2-4ac
Δ = -552-4·52·(-63)
Δ = 16129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16129}=127$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-127}{2*52}=\frac{-72}{104}
=-9/13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+127}{2*52}=\frac{182}{104}
=1+3/4
$